// Copyright The OpenTelemetry Authors // SPDX-License-Identifier: Apache-2.0 package exemplar // import "go.opentelemetry.io/otel/sdk/metric/internal/exemplar" import ( "context" "math" "math/rand" "sync" "time" "go.opentelemetry.io/otel/attribute" ) var ( // rng is used to make sampling decisions. // // Do not use crypto/rand. There is no reason for the decrease in performance // given this is not a security sensitive decision. rng = rand.New(rand.NewSource(time.Now().UnixNano())) // Ensure concurrent safe access to rng and its underlying source. rngMu sync.Mutex ) // random returns, as a float64, a uniform pseudo-random number in the open // interval (0.0,1.0). func random() float64 { // TODO: This does not return a uniform number. rng.Float64 returns a // uniformly random int in [0,2^53) that is divided by 2^53. Meaning it // returns multiples of 2^-53, and not all floating point numbers between 0 // and 1 (i.e. for values less than 2^-4 the 4 last bits of the significand // are always going to be 0). // // An alternative algorithm should be considered that will actually return // a uniform number in the interval (0,1). For example, since the default // rand source provides a uniform distribution for Int63, this can be // converted following the prototypical code of Mersenne Twister 64 (Takuji // Nishimura and Makoto Matsumoto: // http://www.math.sci.hiroshima-u.ac.jp/m-mat/MT/VERSIONS/C-LANG/mt19937-64.c) // // (float64(rng.Int63()>>11) + 0.5) * (1.0 / 4503599627370496.0) // // There are likely many other methods to explore here as well. rngMu.Lock() defer rngMu.Unlock() f := rng.Float64() for f == 0 { f = rng.Float64() } return f } // FixedSize returns a [Reservoir] that samples at most k exemplars. If there // are k or less measurements made, the Reservoir will sample each one. If // there are more than k, the Reservoir will then randomly sample all // additional measurement with a decreasing probability. func FixedSize(k int) Reservoir { r := &randRes{storage: newStorage(k)} r.reset() return r } type randRes struct { *storage // count is the number of measurement seen. count int64 // next is the next count that will store a measurement at a random index // once the reservoir has been filled. next int64 // w is the largest random number in a distribution that is used to compute // the next next. w float64 } func (r *randRes) Offer(ctx context.Context, t time.Time, n Value, a []attribute.KeyValue) { // The following algorithm is "Algorithm L" from Li, Kim-Hung (4 December // 1994). "Reservoir-Sampling Algorithms of Time Complexity // O(n(1+log(N/n)))". ACM Transactions on Mathematical Software. 20 (4): // 481–493 (https://dl.acm.org/doi/10.1145/198429.198435). // // A high-level overview of "Algorithm L": // 0) Pre-calculate the random count greater than the storage size when // an exemplar will be replaced. // 1) Accept all measurements offered until the configured storage size is // reached. // 2) Loop: // a) When the pre-calculate count is reached, replace a random // existing exemplar with the offered measurement. // b) Calculate the next random count greater than the existing one // which will replace another exemplars // // The way a "replacement" count is computed is by looking at `n` number of // independent random numbers each corresponding to an offered measurement. // Of these numbers the smallest `k` (the same size as the storage // capacity) of them are kept as a subset. The maximum value in this // subset, called `w` is used to weight another random number generation // for the next count that will be considered. // // By weighting the next count computation like described, it is able to // perform a uniformly-weighted sampling algorithm based on the number of // samples the reservoir has seen so far. The sampling will "slow down" as // more and more samples are offered so as to reduce a bias towards those // offered just prior to the end of the collection. // // This algorithm is preferred because of its balance of simplicity and // performance. It will compute three random numbers (the bulk of // computation time) for each item that becomes part of the reservoir, but // it does not spend any time on items that do not. In particular it has an // asymptotic runtime of O(k(1 + log(n/k)) where n is the number of // measurements offered and k is the reservoir size. // // See https://en.wikipedia.org/wiki/Reservoir_sampling for an overview of // this and other reservoir sampling algorithms. See // https://github.com/MrAlias/reservoir-sampling for a performance // comparison of reservoir sampling algorithms. if int(r.count) < cap(r.store) { r.store[r.count] = newMeasurement(ctx, t, n, a) } else { if r.count == r.next { // Overwrite a random existing measurement with the one offered. idx := int(rng.Int63n(int64(cap(r.store)))) r.store[idx] = newMeasurement(ctx, t, n, a) r.advance() } } r.count++ } // reset resets r to the initial state. func (r *randRes) reset() { // This resets the number of exemplars known. r.count = 0 // Random index inserts should only happen after the storage is full. r.next = int64(cap(r.store)) // Initial random number in the series used to generate r.next. // // This is set before r.advance to reset or initialize the random number // series. Without doing so it would always be 0 or never restart a new // random number series. // // This maps the uniform random number in (0,1) to a geometric distribution // over the same interval. The mean of the distribution is inversely // proportional to the storage capacity. r.w = math.Exp(math.Log(random()) / float64(cap(r.store))) r.advance() } // advance updates the count at which the offered measurement will overwrite an // existing exemplar. func (r *randRes) advance() { // Calculate the next value in the random number series. // // The current value of r.w is based on the max of a distribution of random // numbers (i.e. `w = max(u_1,u_2,...,u_k)` for `k` equal to the capacity // of the storage and each `u` in the interval (0,w)). To calculate the // next r.w we use the fact that when the next exemplar is selected to be // included in the storage an existing one will be dropped, and the // corresponding random number in the set used to calculate r.w will also // be replaced. The replacement random number will also be within (0,w), // therefore the next r.w will be based on the same distribution (i.e. // `max(u_1,u_2,...,u_k)`). Therefore, we can sample the next r.w by // computing the next random number `u` and take r.w as `w * u^(1/k)`. r.w *= math.Exp(math.Log(random()) / float64(cap(r.store))) // Use the new random number in the series to calculate the count of the // next measurement that will be stored. // // Given 0 < r.w < 1, each iteration will result in subsequent r.w being // smaller. This translates here into the next next being selected against // a distribution with a higher mean (i.e. the expected value will increase // and replacements become less likely) // // Important to note, the new r.next will always be at least 1 more than // the last r.next. r.next += int64(math.Log(random())/math.Log(1-r.w)) + 1 } func (r *randRes) Collect(dest *[]Exemplar) { r.storage.Collect(dest) // Call reset here even though it will reset r.count and restart the random // number series. This will persist any old exemplars as long as no new // measurements are offered, but it will also prioritize those new // measurements that are made over the older collection cycle ones. r.reset() }