gotosocial/vendor/codeberg.org/gruf/go-structr/list.go
kim 095663f5cc
[bugfix] visibility after implicit approval not getting invalidated (#3370)
* replicate issue

* update go-structr to v0.8.10 with internal linked-list fix, small tweaks to caching of interaction requests

* remove debug function

---------

Co-authored-by: tobi <tobi.smethurst@protonmail.com>
2024-09-28 22:47:46 +02:00

156 lines
2.6 KiB
Go

package structr
import (
"sync"
"unsafe"
)
// elem represents an elem
// in a doubly-linked list.
type list_elem struct {
next *list_elem
prev *list_elem
// data is a ptr to the
// value this linked list
// element is embedded-in.
data unsafe.Pointer
}
// list implements a doubly-linked list, where:
// - head = index 0 (i.e. the front)
// - tail = index n-1 (i.e. the back)
type list struct {
head *list_elem
tail *list_elem
len int
}
var list_pool sync.Pool
// new_list returns a new prepared list.
func new_list() *list {
v := list_pool.Get()
if v == nil {
v = new(list)
}
list := v.(*list)
return list
}
// free_list releases the list.
func free_list(list *list) {
list.head = nil
list.tail = nil
list.len = 0
list_pool.Put(list)
}
// push_front will push the given elem to front (head) of list.
func (l *list) push_front(elem *list_elem) {
// Set new head.
oldHead := l.head
l.head = elem
if oldHead != nil {
// Link to old head
elem.next = oldHead
oldHead.prev = elem
} else {
// First in list.
l.tail = elem
}
// Incr count
l.len++
}
// push_back will push the given elem to back (tail) of list.
func (l *list) push_back(elem *list_elem) {
// Set new tail.
oldTail := l.tail
l.tail = elem
if oldTail != nil {
// Link to old tail
elem.prev = oldTail
oldTail.next = elem
} else {
// First in list.
l.head = elem
}
// Incr count
l.len++
}
// move_front will move given elem to front (head) of list.
// if it is already at front this call is a no-op.
func (l *list) move_front(elem *list_elem) {
if elem == l.head {
return
}
l.remove(elem)
l.push_front(elem)
}
// move_back will move given elem to back (tail) of list,
// if it is already at back this call is a no-op.
func (l *list) move_back(elem *list_elem) {
if elem == l.tail {
return
}
l.remove(elem)
l.push_back(elem)
}
// remove will remove given elem from list.
func (l *list) remove(elem *list_elem) {
// Get linked elems.
next := elem.next
prev := elem.prev
// Unset elem.
elem.next = nil
elem.prev = nil
switch {
// elem is ONLY one in list.
case next == nil && prev == nil:
l.head = nil
l.tail = nil
// elem is front in list.
case next != nil && prev == nil:
l.head = next
next.prev = nil
// elem is last in list.
case prev != nil && next == nil:
l.tail = prev
prev.next = nil
// elem in middle of list.
default:
next.prev = prev
prev.next = next
}
// Decr count
l.len--
}
// rangefn will range all elems in list, passing each to fn.
func (l *list) rangefn(fn func(*list_elem)) {
if fn == nil {
panic("nil fn")
}
for e := l.head; //
e != nil; //
{
n := e.next
fn(e)
e = n
}
}